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5x^2+100x+375=0
a = 5; b = 100; c = +375;
Δ = b2-4ac
Δ = 1002-4·5·375
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-50}{2*5}=\frac{-150}{10} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+50}{2*5}=\frac{-50}{10} =-5 $
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