5x2+11x-7=0

Solution for 5x2+11x-7=0 equation:

5x^2+11x-7=0

a = 5; b = 11; c = -7;
Δ = b2-4ac
Δ = 112-4·5·(-7)
Δ = 261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{261}=\sqrt{9*29}=\sqrt{9}*\sqrt{29}=3\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3\sqrt{29}}{2*5}=\frac{-11-3\sqrt{29}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3\sqrt{29}}{2*5}=\frac{-11+3\sqrt{29}}{10}
$