5x2+14x-87=0

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Solution for 5x2+14x-87=0 equation:



5x^2+14x-87=0
a = 5; b = 14; c = -87;
Δ = b2-4ac
Δ = 142-4·5·(-87)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-44}{2*5}=\frac{-58}{10} =-5+4/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+44}{2*5}=\frac{30}{10} =3 $

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