5x2+20=20x

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Solution for 5x2+20=20x equation: 



5x^2+20=20x

We move all terms to the left:

5x^2+20-(20x)=0

a = 5; b = -20; c = +20;
Δ = b2-4ac
Δ = -202-4·5·20
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{10}=2$

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