5x2+20=4

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Solution for 5x2+20=4 equation: 



5x^2+20=4

We move all terms to the left:

5x^2+20-(4)=0

We add all the numbers together, and all the variables

5x^2+16=0

a = 5; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·5·16
Δ = -320
Delta is less than zero, so there is no solution for the equation

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