5x2+26x+10=5

Solution for 5x2+26x+10=5 equation:

5x^2+26x+10=5

We move all terms to the left:

5x^2+26x+10-(5)=0

We add all the numbers together, and all the variables

5x^2+26x+5=0

a = 5; b = 26; c = +5;
Δ = b2-4ac
Δ = 262-4·5·5
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-24}{2*5}=\frac{-50}{10}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+24}{2*5}=\frac{-2}{10}
=-1/5
$