5x2+2x-2800=0

Solution for 5x2+2x-2800=0 equation:

5x^2+2x-2800=0

a = 5; b = 2; c = -2800;
Δ = b2-4ac
Δ = 22-4·5·(-2800)
Δ = 56004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56004}=\sqrt{4*14001}=\sqrt{4}*\sqrt{14001}=2\sqrt{14001}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{14001}}{2*5}=\frac{-2-2\sqrt{14001}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{14001}}{2*5}=\frac{-2+2\sqrt{14001}}{10}
$