5x2+340x-600=0

Solution for 5x2+340x-600=0 equation:

5x^2+340x-600=0

a = 5; b = 340; c = -600;
Δ = b2-4ac
Δ = 3402-4·5·(-600)
Δ = 127600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{127600}=\sqrt{400*319}=\sqrt{400}*\sqrt{319}=20\sqrt{319}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(340)-20\sqrt{319}}{2*5}=\frac{-340-20\sqrt{319}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(340)+20\sqrt{319}}{2*5}=\frac{-340+20\sqrt{319}}{10}
$