5x2+37x-130=0

Solution for 5x2+37x-130=0 equation:

5x^2+37x-130=0

a = 5; b = 37; c = -130;
Δ = b2-4ac
Δ = 372-4·5·(-130)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-63}{2*5}=\frac{-100}{10}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+63}{2*5}=\frac{26}{10}
=2+3/5
$