5x2+43=(x-1)(x+2)

Solution for 5x2+43=(x-1)(x+2) equation:

5x^2+43=(x-1)(x+2)

We move all terms to the left:

5x^2+43-((x-1)(x+2))=0

We multiply parentheses ..

5x^2-((+x^2+2x-1x-2))+43=0


We calculate terms in parentheses: -((+x^2+2x-1x-2)), so:

(+x^2+2x-1x-2)

We get rid of parentheses

x^2+2x-1x-2

We add all the numbers together, and all the variables

x^2+x-2

Back to the equation:

-(x^2+x-2)


We get rid of parentheses

5x^2-x^2-x+2+43=0

We add all the numbers together, and all the variables

4x^2-1x+45=0

a = 4; b = -1; c = +45;
Δ = b2-4ac
Δ = -12-4·4·45
Δ = -719
Delta is less than zero, so there is no solution for the equation