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5x^2+4=9x+2x^2
We move all terms to the left:
5x^2+4-(9x+2x^2)=0
We get rid of parentheses
5x^2-2x^2-9x+4=0
We add all the numbers together, and all the variables
3x^2-9x+4=0
a = 3; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·3·4
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{33}}{2*3}=\frac{9-\sqrt{33}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{33}}{2*3}=\frac{9+\sqrt{33}}{6} $
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