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5x^2+500=844.45
We move all terms to the left:
5x^2+500-(844.45)=0
We add all the numbers together, and all the variables
5x^2-344.45=0
a = 5; b = 0; c = -344.45;
Δ = b2-4ac
Δ = 02-4·5·(-344.45)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-83}{2*5}=\frac{-83}{10} =-8+3/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+83}{2*5}=\frac{83}{10} =8+3/10 $
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