5x2+50x-25=0

Solution for 5x2+50x-25=0 equation:

5x^2+50x-25=0

a = 5; b = 50; c = -25;
Δ = b2-4ac
Δ = 502-4·5·(-25)
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{30}}{2*5}=\frac{-50-10\sqrt{30}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{30}}{2*5}=\frac{-50+10\sqrt{30}}{10}
$