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5x^2+50x=-125
We move all terms to the left:
5x^2+50x-(-125)=0
We add all the numbers together, and all the variables
5x^2+50x+125=0
a = 5; b = 50; c = +125;
Δ = b2-4ac
Δ = 502-4·5·125
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-50}{10}=-5$
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