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5x^2+56x+11=0
a = 5; b = 56; c = +11;
Δ = b2-4ac
Δ = 562-4·5·11
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-54}{2*5}=\frac{-110}{10} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+54}{2*5}=\frac{-2}{10} =-1/5 $
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