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5x^2+58x=3x
We move all terms to the left:
5x^2+58x-(3x)=0
We add all the numbers together, and all the variables
5x^2+55x=0
a = 5; b = 55; c = 0;
Δ = b2-4ac
Δ = 552-4·5·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-55}{2*5}=\frac{-110}{10} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+55}{2*5}=\frac{0}{10} =0 $
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