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5x^2+65x+180=0
a = 5; b = 65; c = +180;
Δ = b2-4ac
Δ = 652-4·5·180
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-25}{2*5}=\frac{-90}{10} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+25}{2*5}=\frac{-40}{10} =-4 $
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