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5x^2+6x-42=312512-x
We move all terms to the left:
5x^2+6x-42-(312512-x)=0
We add all the numbers together, and all the variables
5x^2+6x-(-1x+312512)-42=0
We get rid of parentheses
5x^2+6x+1x-312512-42=0
We add all the numbers together, and all the variables
5x^2+7x-312554=0
a = 5; b = 7; c = -312554;
Δ = b2-4ac
Δ = 72-4·5·(-312554)
Δ = 6251129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{6251129}}{2*5}=\frac{-7-\sqrt{6251129}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{6251129}}{2*5}=\frac{-7+\sqrt{6251129}}{10} $
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