If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+8x-4=9x
We move all terms to the left:
5x^2+8x-4-(9x)=0
We add all the numbers together, and all the variables
5x^2-1x-4=0
a = 5; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·5·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-9}{2*5}=\frac{-8}{10} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+9}{2*5}=\frac{10}{10} =1 $
| 22+4y-14=16 | | 3x+20=x–8 | | m−–9=18 | | 6y-4=155 | | 3/2b-7/3b=5/6 | | 3x-5x=11;x=1,0,1 | | (11+x)x3/4=27 | | 7x-20=-83 | | 9(8-5d)=17 | | 4+14x=46 | | 80.8=-3.2+r/2 | | -10+m=-m | | 4/3b-7/3b=5/6 | | 3x+18-2x=8x-10-x | | 78=3(p+11) | | -9x-4=-76 | | X+2x=3x-1 | | 4x=5(x+8) | | -14+12x=3x+22 | | 12m+5/3=9 | | R+R+10+2(r+10)=130 | | t+28=12 | | 3q(q-3)=12 | | –6r+7=–5r | | 31=-3p+-32 | | -x^2+14x-2x^2+6x=28 | | -6-4s=8-2s | | -8x+2=7(-2-4x)+4x | | y=|9|-9 | | -4=-1/3(x-9) | | (6m+6)+36=90 | | 39x+3=40 |