5x2-(x+2)(x-3)+2(x+3)=6x2+3x+12

Solution for 5x2-(x+2)(x-3)+2(x+3)=6x2+3x+12 equation:

5x^2-(x+2)(x-3)+2(x+3)=6x^2+3x+12

We move all terms to the left:

5x^2-(x+2)(x-3)+2(x+3)-(6x^2+3x+12)=0

We multiply parentheses

5x^2-(x+2)(x-3)+2x-(6x^2+3x+12)+6=0

We get rid of parentheses

5x^2-6x^2-(x+2)(x-3)+2x-3x-12+6=0

We multiply parentheses ..

5x^2-6x^2-(+x^2-3x+2x-6)+2x-3x-12+6=0

We add all the numbers together, and all the variables

-1x^2-(+x^2-3x+2x-6)-1x-6=0

We get rid of parentheses

-1x^2-x^2+3x-2x-1x+6-6=0

We add all the numbers together, and all the variables

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$