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5x^2-10x=840=0
We move all terms to the left:
5x^2-10x-(840)=0
a = 5; b = -10; c = -840;
Δ = b2-4ac
Δ = -102-4·5·(-840)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-130}{2*5}=\frac{-120}{10} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+130}{2*5}=\frac{140}{10} =14 $
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