If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-128+3=0
We add all the numbers together, and all the variables
5x^2-125=0
a = 5; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·5·(-125)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50}{2*5}=\frac{50}{10} =5 $
| −3=x+5−3=x+5 | | 23-b/6=-19 | | 6x+5/4x-3=0 | | 14x–3=5x+15 | | 8x^2-1=-5 | | 7b-5b=-2 | | M=211-3m | | 7n-1=5n+11 | | 10a-9a=14 | | 5=7x=11+7x | | -29+x=13-2x | | 1=2k–13 | | 11(k-1)=7(k-15) | | 2x+15=7x-9 | | 8(x-9)=-6x+12 | | 2(4x-4)×4x+5=-111 | | 12z-3z=18 | | 4(y-11)=36 | | 34+4y-12=17y-14-4y | | -5x-(-4-3x)=-4(2x-5) | | X+9=10x+27 | | (x+2)(x-4)=41-2x | | 12x+12(x+10)=x48 | | 7x+156=9x+134 | | 6(2x+2)=4(3x+6) | | x=4812x+12(x+10) | | p/6=-5 | | 15.91-10.5g=-14.8g | | 9x+6=−2 | | 4+q6=472 | | 6x=-2(7) | | 2x2+7x+3=0 |