5x2-14x-16=0

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Solution for 5x2-14x-16=0 equation:



5x^2-14x-16=0
a = 5; b = -14; c = -16;
Δ = b2-4ac
Δ = -142-4·5·(-16)
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{129}}{2*5}=\frac{14-2\sqrt{129}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{129}}{2*5}=\frac{14+2\sqrt{129}}{10} $

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