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5x^2-180x+900=0
a = 5; b = -180; c = +900;
Δ = b2-4ac
Δ = -1802-4·5·900
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-120}{2*5}=\frac{60}{10} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+120}{2*5}=\frac{300}{10} =30 $
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