If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-18x=9
We move all terms to the left:
5x^2-18x-(9)=0
a = 5; b = -18; c = -9;
Δ = b2-4ac
Δ = -182-4·5·(-9)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{14}}{2*5}=\frac{18-6\sqrt{14}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{14}}{2*5}=\frac{18+6\sqrt{14}}{10} $
| 3x+-8=-5x+12. | | (m-4)/3=5 | | 550=x+1.2x | | x^2+14*x=100 | | 6x−13=29 | | 2x^2/(1-x)(2-x)=115 | | 45=6y;y | | 3x+5=2x+12= | | (3x-8)²=81 | | r–20=30 | | -8.25+12-1.75x=10.5+1.75 | | 1/3x=3+1/4x | | p-31/6=11/2 | | 2x-7+12x=4(5x-3)+2 | | X2-10x=39 | | 2(x-3)-5(x-1)=1/2 | | 3x+24=36;x | | 11=n-8 | | X2-7x=44 | | X^2y+(y)^2=0 | | 1(v-45)=2(v-68) | | 2x•(x+5)-x^2+7=x^2-(3x-5/3) | | 2x•(x+5)-x^2+7=x^2-(3x-5/3 | | 6x−4=−(32x−2) | | 0.75=0.41+0.5x | | (V-45)=2(v-68) | | (3x+12)+(2x+23)+(180-(6x+18))=180 | | 3.p-3.7=2.4 | | 3x5=2x+12= | | V-45=2(v-68) | | 26−8x=−(7−35x) | | 2k+5-3=10 |