5x2-26x+5=0

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Solution for 5x2-26x+5=0 equation:



5x^2-26x+5=0
a = 5; b = -26; c = +5;
Δ = b2-4ac
Δ = -262-4·5·5
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-24}{2*5}=\frac{2}{10} =1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+24}{2*5}=\frac{50}{10} =5 $

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