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5x^2-2x+0.2=0
a = 5; b = -2; c = +0.2;
Δ = b2-4ac
Δ = -22-4·5·0.2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{2}{10}=1/5$
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