5x2-2x+16=4x2+6x

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Solution for 5x2-2x+16=4x2+6x equation: 



5x^2-2x+16=4x^2+6x

We move all terms to the left:

5x^2-2x+16-(4x^2+6x)=0

We get rid of parentheses

5x^2-4x^2-2x-6x+16=0

We add all the numbers together, and all the variables

x^2-8x+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{2}=4$

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