5x2-3(2x+1)=5x2-6x2-6x-3

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Solution for 5x2-3(2x+1)=5x2-6x2-6x-3 equation: 



5x^2-3(2x+1)=5x^2-6x^2-6x-3

We move all terms to the left:

5x^2-3(2x+1)-(5x^2-6x^2-6x-3)=0

We multiply parentheses

5x^2-(5x^2-6x^2-6x-3)-6x-3=0

We get rid of parentheses

5x^2-5x^2+6x^2+6x-6x+3-3=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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