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5x^2-3125=0
a = 5; b = 0; c = -3125;
Δ = b2-4ac
Δ = 02-4·5·(-3125)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-250}{2*5}=\frac{-250}{10} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+250}{2*5}=\frac{250}{10} =25 $
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