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5x^2-32x-21=0
a = 5; b = -32; c = -21;
Δ = b2-4ac
Δ = -322-4·5·(-21)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-38}{2*5}=\frac{-6}{10} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+38}{2*5}=\frac{70}{10} =7 $
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