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5x^2-3x=7-(2x+9)
We move all terms to the left:
5x^2-3x-(7-(2x+9))=0
We calculate terms in parentheses: -(7-(2x+9)), so:We get rid of parentheses
7-(2x+9)
determiningTheFunctionDomain -(2x+9)+7
We get rid of parentheses
-2x-9+7
We add all the numbers together, and all the variables
-2x-2
Back to the equation:
-(-2x-2)
5x^2-3x+2x+2=0
We add all the numbers together, and all the variables
5x^2-1x+2=0
a = 5; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·5·2
Δ = -39
Delta is less than zero, so there is no solution for the equation
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