5x2-41x+8=0

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Solution for 5x2-41x+8=0 equation:



5x^2-41x+8=0
a = 5; b = -41; c = +8;
Δ = b2-4ac
Δ = -412-4·5·8
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-39}{2*5}=\frac{2}{10} =1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+39}{2*5}=\frac{80}{10} =8 $

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