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5x^2-4x+0.8=0
a = 5; b = -4; c = +0.8;
Δ = b2-4ac
Δ = -42-4·5·0.8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{10}=2/5$
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