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5x^2-4x+1=-3x^2+x-3
We move all terms to the left:
5x^2-4x+1-(-3x^2+x-3)=0
We get rid of parentheses
5x^2+3x^2-x-4x+3+1=0
We add all the numbers together, and all the variables
8x^2-5x+4=0
a = 8; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·8·4
Δ = -103
Delta is less than zero, so there is no solution for the equation
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