5x2-4x-12=0

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Solution for 5x2-4x-12=0 equation:



5x^2-4x-12=0
a = 5; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·5·(-12)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*5}=\frac{-12}{10} =-1+1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*5}=\frac{20}{10} =2 $

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