If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-4x=1
We move all terms to the left:
5x^2-4x-(1)=0
a = 5; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·5·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6}{2*5}=\frac{-2}{10} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6}{2*5}=\frac{10}{10} =1 $
| 10=-1/4x+14 | | 3(x-2)2=-9 | | 19x-17=-26 | | 39x-2)2=-9 | | 2xx7=4x-1 | | 6x+7=-23-23-9x | | 6m+12=6m+12 | | x+41/2=44/5 | | 2(x−4)=−16 | | 600=12(u+26) | | -1/5c=35= | | 0=8(f+7) | | 8.9+0.9x=14.0 | | 94-26s=718 | | 14d+3=14d+16+13d | | -11⁄5c=35= | | 2*x=0.8 | | 7x-8/x^2-1=0 | | -11⁄5c=35 | | -3z-7+12=-2z-14 | | -6(r-89)=-18 | | 4.1+x=4.1 | | 2.3y=-20.7= | | ((5(x-2))/(x+2)-((2(x-3))/(x+3))=3 | | 8-3(x+5)=5(x-4) | | 2x−8=−32 | | y-20=3 | | 7.4w-15.65=18.88+9.5w+2.01 | | 4p=48= | | 2-3(3-х)=4x | | 13.65=h-4.88 | | 4(2x+3)=13x-20+2x |