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5x^2-56x-16=0
a = 5; b = -56; c = -16;
Δ = b2-4ac
Δ = -562-4·5·(-16)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-24\sqrt{6}}{2*5}=\frac{56-24\sqrt{6}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+24\sqrt{6}}{2*5}=\frac{56+24\sqrt{6}}{10} $
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