5x2/7=(x)1/7

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Solution for 5x2/7=(x)1/7 equation:


x in (-oo:+oo)

(5*x^2)/7 = (x^1)/7 // - (x^1)/7

(5*x^2)/7-((x^1)/7) = 0

(5*x^2)/7-(x/7) = 0

5/7*x^2-1/7*x = 0

DELTA = (-1/7)^2-(0*5/7*4)

DELTA = 1/49

DELTA > 0

x = ((1/49)^(1/2)+1/7)/(5/7*2) or x = (1/7-(1/49)^(1/2))/(5/7*2)

x = 1/5 or x = 0

x in { 0, 1/5 }

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