If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2=-35x
We move all terms to the left:
5x^2-(-35x)=0
We get rid of parentheses
5x^2+35x=0
a = 5; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·5·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*5}=\frac{-70}{10} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*5}=\frac{0}{10} =0 $
| 4(y-3)-5=-3(-6y+3)-2y | | 2x-12=28× | | 7=w+9/5 | | -3=65)x+8=18 | | y+3=2y+27 | | 3–2p=5+43p | | x–5=–2x–17 | | 4+5n= | | -6+-2z=18 | | v/6+24=28 | | 33=f/8+25 | | -6(2+8p)+4=37-3p | | 7(p-77)=91 | | −9x+4=6 | | 5d+3+2d=1d+10 | | 2k+28=60 | | 20=5(j-93) | | 3(x−4)=−12(24−6x) | | j/9+16=21 | | 2(b+25)=-12 | | 1/4x−3=−4 | | 2(b+25)=–12 | | f=5/9(f-32) | | b+19/7=8 | | 1.1x-2=9.1 | | 8n2-8=-18 | | x/4−3=−4 | | 5x-3=13+4 | | 2x×x=200 | | 2(x−30)=10 | | n2-6=48 | | 100=x*0.15 |