5x2=106

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Solution for 5x2=106 equation:



5x^2=106
We move all terms to the left:
5x^2-(106)=0
a = 5; b = 0; c = -106;
Δ = b2-4ac
Δ = 02-4·5·(-106)
Δ = 2120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2120}=\sqrt{4*530}=\sqrt{4}*\sqrt{530}=2\sqrt{530}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{530}}{2*5}=\frac{0-2\sqrt{530}}{10} =-\frac{2\sqrt{530}}{10} =-\frac{\sqrt{530}}{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{530}}{2*5}=\frac{0+2\sqrt{530}}{10} =\frac{2\sqrt{530}}{10} =\frac{\sqrt{530}}{5} $

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