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5x^2=11
We move all terms to the left:
5x^2-(11)=0
a = 5; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·5·(-11)
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{55}}{2*5}=\frac{0-2\sqrt{55}}{10} =-\frac{2\sqrt{55}}{10} =-\frac{\sqrt{55}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{55}}{2*5}=\frac{0+2\sqrt{55}}{10} =\frac{2\sqrt{55}}{10} =\frac{\sqrt{55}}{5} $
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