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5x^2=12-2x
We move all terms to the left:
5x^2-(12-2x)=0
We add all the numbers together, and all the variables
5x^2-(-2x+12)=0
We get rid of parentheses
5x^2+2x-12=0
a = 5; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·5·(-12)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{61}}{2*5}=\frac{-2-2\sqrt{61}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{61}}{2*5}=\frac{-2+2\sqrt{61}}{10} $
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