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5x^2=1620
We move all terms to the left:
5x^2-(1620)=0
a = 5; b = 0; c = -1620;
Δ = b2-4ac
Δ = 02-4·5·(-1620)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*5}=\frac{-180}{10} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*5}=\frac{180}{10} =18 $
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