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5x^2=2.5x+8
We move all terms to the left:
5x^2-(2.5x+8)=0
We get rid of parentheses
5x^2-2.5x-8=0
a = 5; b = -2.5; c = -8;
Δ = b2-4ac
Δ = -2.52-4·5·(-8)
Δ = 166.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{166.25}}{2*5}=\frac{2.5-\sqrt{166.25}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{166.25}}{2*5}=\frac{2.5+\sqrt{166.25}}{10} $
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