5x2=4+

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Solution for 5x2=4+ equation:



5x^2=4+
We move all terms to the left:
5x^2-(4+)=0
We add all the numbers together, and all the variables
5x^2-0=0
We add all the numbers together, and all the variables
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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