If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2=45
We move all terms to the left:
5x^2-(45)=0
a = 5; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·5·(-45)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*5}=\frac{-30}{10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*5}=\frac{30}{10} =3 $
| (6/3)^-4×(6/3)^3m=(6/3)^5 | | 12x+14=74 | | -6x+17=4x-3 | | x*1.2=111 | | 13x-5=7x+1 | | 5x+(-3)=11 | | 3(3u-1)=2/u | | (x^2+2.5)^2=3600 | | 1.3=y/1.2 | | (2x+6)(2x+6)=74 | | n(n-1)(n+1)=990 | | 0=128-120x-x^2 | | 2x√3=24 | | (5x-4)(4x+7)=0 | | 3s+13=0 | | X+5÷3=1÷7x-8÷9 | | 6x+7÷3x+2=4x+5÷2x+3 | | 3x^2+31-6.9=0 | | w^2-23w+120=0 | | 0.04(4t-4)=0.16(t+2)-0.48 | | 0.4x+0.2=0.8x-0.6 | | 0.04x+0.2=0.8x-0.6 | | 0.1-0.01(x+3)=-0.03(3-x) | | (x-2)^2-9=7 | | X^+2x-120=0 | | (10/x+2)+(6/x-2)=2 | | 0.01-0.01(x+3)=-0.03(3-x) | | 5(x-2)+6=2x+3(-3+x) | | 16^4x=8 | | 2(2n+3)=8(3n+5)+8 | | 26x+10=3(7x+3)+5x+1 | | 28x^2=23x+15 |