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5x^2=4x-1
We move all terms to the left:
5x^2-(4x-1)=0
We get rid of parentheses
5x^2-4x+1=0
a = 5; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·5·1
Δ = -4
Delta is less than zero, so there is no solution for the equation
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