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5x^2=625
We move all terms to the left:
5x^2-(625)=0
a = 5; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·5·(-625)
Δ = 12500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12500}=\sqrt{2500*5}=\sqrt{2500}*\sqrt{5}=50\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{5}}{2*5}=\frac{0-50\sqrt{5}}{10} =-\frac{50\sqrt{5}}{10} =-5\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{5}}{2*5}=\frac{0+50\sqrt{5}}{10} =\frac{50\sqrt{5}}{10} =5\sqrt{5} $
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