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5x=(-30/7)
We move all terms to the left:
5x-((-30/7))=0
We multiply all the terms by the denominator
5x*7))-((-30=0
Wy multiply elements
35x^2-30=0
a = 35; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·35·(-30)
Δ = 4200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4200}=\sqrt{100*42}=\sqrt{100}*\sqrt{42}=10\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{42}}{2*35}=\frac{0-10\sqrt{42}}{70} =-\frac{10\sqrt{42}}{70} =-\frac{\sqrt{42}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{42}}{2*35}=\frac{0+10\sqrt{42}}{70} =\frac{10\sqrt{42}}{70} =\frac{\sqrt{42}}{7} $
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